Question

помогите пожалуйста Алгебра n156

Answer 1

${7}^{2} = 49 \\\\ {0.5}^{3} = { (\frac{1}{2}) }^{3} = \frac{1}{8} \\\\ {1.2}^{2} = 1.44 \\\\ { - 1}^{7} = - 1 \\\\ { - 0.8}^{3} = - 0.512 \\\\ {( \frac{1}{6} )}^{4} = \frac{1}{1296} \\\\ {( - \frac{1}{2} )}^{6} = \frac{1}{64} \\\\ { (- 3 \frac{1}{3}) }^{3} = {( - \frac{10}{3}) }^{3} = - 37 \frac{1}{27}$