Question

32^2/3 =
3^-4 =
log32 43 - 2log2 1 =

Answer 1

$32^{\frac{2}{3} } =\sqrt[3]{32^{2} } =\sqrt[3]{1024} =8\sqrt[3]{2} \\ \\ 3^{-4} =\frac{1}{3^{4} } =\frac{1}{81}$

㏒₃₂(43)-2㏒₂(1)=㏒₃₂(43)-2·0=㏒₃₂(43)-0=㏒₃₂(43)=㏒₂⁵(43)=(1/5)㏒₂(43)