Question

$y'=(\frac{e^x+\pi } \sqrt{x}} )'$
Найти первую производную

Answer 1

$y = \frac{e^{x}+\pi}{\sqrt{x}}$

$y' = (\frac{e^{x}+\pi}{\sqrt{x}})' = \frac{(e^{x}+\pi)'*\sqrt{x} - (e^{x}+\pi)*\sqrt{x}'}{\sqrt{x}^2} = \\= \frac{e^{x}*\sqrt{x} - \frac{e^{x}+\pi}{2\sqrt{x}}}{x}$