Question

$2^x - 2^{x-2} = 3$
Найти х

Answer 1

$2^x - 2^{x-2} = 3 \\ {2}^{x - 2 + 2} - 2 ^{x - 2} = 3 \\ ( {2}^{2} - 1) \times {2}^{x - 2} = 3 \\ {2}^{x - 2} = 1 \\ x - 2 = 0 \\ x = 2$

Answer 2

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