Question

Найдите степень одночлена
1) -b^4b^4b
2) -a^5 (-a^8)
3)5/24k^t (-3/10t^6)

Answer 1

1)$-b^4*b^4*b = -b^{4+4+1} = -b^9$

2)$-a^5*(-a^8) = a^{5+8} = a^{13}$

3)$\frac{5}{24}*k^{t(-\frac{3}{10}t^6)}= \frac{5}{24}*k^{-\frac{3}{10}t^7}$