Question

1/4х²-2х+4=0.
Помогите,пожалуйста.

Answer 1

$\frac{1}{4} x {}^{2} - 2x + 4 = 0 \\ {x}^{2} - 8x + 16 = 0 \\ (x - 4) {}^{2} = 0 \\ x - 4 = 0 \\ x = 4$
Ответ: х = 4

Answer 2

х^2-8x+16=0

(x-4)^2=0

x-4=0

x=4