Question

Вычислите(подробно пожалуйста)
а)$0.3*\sqrt{10}*\sqrt{6}*\sqrt{15}-0.1*\frac{2}{3}:\sqrt{\frac{1}{0.09} }$
б)$64^\frac{5}{6}-(0.125)^-^\frac{1}{3}-32*2^-^4*16^-^1^\frac{1}{2}+(3^0)^4*4$

Answer 1

$a)0,3*\sqrt{10}*\sqrt{6} *\sqrt{15} -0,1*\frac{2}{3}:\sqrt{\frac{1}{0,09}}=0,3*\sqrt{2*5*2*3*3*5}-0,1*\frac{2}{3}:\frac{1}{0,3}=0,3*\sqrt{2^{2}*3^{2}*5^{2}}-0,1*\frac{2}{3}*0,3=0,3*2*3*5-0,1*0,2=9-0,02=8,98\\64^{\frac{5}{6}}-(0,125)^{-\frac{1}{3}}-32*2^{-4}*16^{-1\frac{1}{2}}+(3^{0})^{4} =(2^{6})^{\frac{5}{6}}-(\frac{1}{8})^{-\frac{1}{3}} -32*\frac{1}{16}*(4^{2})^{-\frac{3}{2}}+1^{4} =2^{5}-(2^{-3})^{-\frac{1}{3}}-2*4^{-3}+1=32-2-\frac{2}{4^{3}}+1=31-\frac{1}{32}=30\frac{31}{32}$=30,96875