Question

8*7^(2*x^2-x)-7*8^(2*x^2-x)=0

Answer 1

$8 \times {7}^{2 {x}^{2} - x} = 7 \times {8}^{2 {x}^{2} - x } \\( { \frac{7}{8} })^{2 {x}^{2} - x} = \frac{7}{8}$
2х^2-х=1
2х^2-х-1=0
х1=1
х2=-1/2