Question

Представит число в десятичной системе исчисления

Answer 1

1010111(2) = 87(10)
$1010111 = 1 \times 2 {}^{6} + 0 \times 2 {}^{5} + 1 \times 2 {}^{4} + 0 \times 2 {}^{3} + 1 \times 2{}^{2} + 1 \times 2 {}^{1} + 1 \times {2}^{0} = 64 + 0 + 16 + 0 + 4 + 2 + 1 = 87$
673(8) = 443(10)
$673 = 6 \times 8 {}^{2} + 7 \times 8 {}^{1} + 3 \times {8}^{0} = 384 + 56 + 3 = 443$
8CB(16) = 2251(10)
$8cb = 8 \times 16 {}^{2} + 12 \times 16 {}^{1} + 11 \times 16 {}^{0} = 2048 + 192 + 11 = 2251$
784(9) = 643(10)
$784 = 7 \times {9}^{2} + 8 \times {9}^{1} + 4 \times {9}^{0} = 567 + 72 + 4 = 643$