Question

Помогите пожалуйста

Answer 1

$\frac{9a^{3}b^{7}c^{3}}{27a^{2}b^{9}c^{3}}=\frac{a}{3b^{2}}\\\frac{5-a}{x-y}-\frac{5+a}{y-x}=\frac{5-a}{x-y}+\frac{5+a}{x-y}=\frac{5-a+5+a}{x-y}=\frac{10}{x-y}\\\frac{2a-2}{x^{2}-y^{2}}*\frac{y+x}{a-1} =\frac{2(a-1)}{(x-y)(x+y)}*\frac{y+x}{a-1}=\frac{2}{x-y}}$

Answer 2

$\frac{9a^{3}b^{7}c^{3}}{27a^{2}b^{9}c^{3}} =\frac{a}{3b^{2} }$

$\frac{5-a}{x-y} - \frac{5+a}{y-x}= \frac{5-a}{x-y} + \frac{5+a}{x-y}=\frac{5-a+5+a}{x-y} =\frac{10}{x-y}$

$\frac{2a-2}{x^{2}-y^{2}} * \frac{y+x}{a-1} = \frac{2(a-1)}{(x-y)(x+y)} * \frac{y+x}{a-1} = \frac{2}{x-y}$