Question

Помогите пожалуйста! 3 задания!

Answer 1

$1)\frac{1-3k}{3}:\frac{18k-6}{6k} =\frac{1-3k}{3}*\frac{6k}{6(3k-1)}=-\frac{k}{3}\\2)\frac{s^{2} +6s+9}{s+7}*\frac{14+2s}{s+3}=\frac{(s+3)^{2}}{s+7}*\frac{2(7+s)}{s+3}=2s+6\\(\frac{q}{u^{2}})^{15}*(\frac{u^{3} }{q^{4}} )^{4}=\frac{q^{15} }{u^{30}}*\frac{u^{12} }{q^{16} }=\frac{1}{u^{18}*q}$

Answer 2

$1)\frac{1-3k}{3}*\frac{6k}{18k-6}=\frac{1-3k}{3}*\frac{-k}{1-3k}=\frac{-k}{3}$

$2)\frac{(s+3)^2}{s+7}\frac{2(s+7)}{s+3}=2s+6;$

$3)\frac{q^{15}}{u^{30}}*\frac{u^{12}}{q^{16}}=\frac{1}{u^{18}q}$