Question

помогите пожалуйста!!!!!!!!!

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$\frac{k}{4t-8}-\frac{k}{8t-16}=\frac{k}{4(t-2)}-\frac{k}{8(t-2)}=\frac{2k-k}{8(t-2)}=\frac{1*k}{8(t-2)}$