Предмет: Алгебра, автор: aisaradzabova569

c(-3;6),b(2:-2) a=1/3c-b найти длину вектора a и координаты вектораaa

Ответы

Автор ответа: Lesben

1

c(-3,6),b(2,-2)

a=(1/3)c-b=(-1,2)-(2,-2)=(-3,4)

/a/=√((-3)²+4²)=√(9+16)=√25=5

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