Question

разложите на множители квадратный трехчлен 8x^2-5x-3

Answer 1

Д=25+4×8×3=121
х=5+-11/16
х1=1
х2=-3/8
(8х+3)(х-1)

Answer 2

$8 {x}^{2} - 5x - 3$
$d = {b}^{2} - 4ac = 25 - 4 \times 8 \times - 3 = 121$
$x1 = \frac{5 + 11}{16} = 1$
$x2 = \frac{5 - 11}{16} = - \frac { 3}{8}$
$a(x - x1) \times (x - x2)$
$8(x - 1) \times (x + \frac{3}{8} )$