Question

тема :$x^{2} -6x +10=0$комплексные числа

Answer 1

${x}^{2} - 6x + 10 = 0 \\ ( {x}^{2} - 6x + 9) + 1 = 0 \\ (x - 3)^{2} + 1 = 0 \\ (x - 3) ^{2} = - 1 \\ x - 3 =±i \\ \\ x_{1,2} = 3±i$