Question

Помогите упростить!  во вложениях

Answer 1

$frac{3-x^2}{x^2-1} + frac{3x}{x^2-1} : frac{x}{x-1} + frac{x+1}{x+1} = frac{3-x^2}{x^2-1} + frac{3x(x-1)}{x(x-1)(x+1)} + frac{x+1}{x+1} = \ = frac{3-x^2}{x^2-1} + frac{3}{x+1} + frac{x+1}{x+1} = frac{3-x^2}{x^2-1} + frac{x+4}{x+1} = \ =frac{3-x^2+(x+4)(x-1)}{x^2-1} = frac{3-x^2+x^2+4x-x-4}{x^2-1} = frac{3x-1}{x^2-1}$