Question

|-3,(6)+2 1/4|-|-5,3+2,(3)|

Answer 1

|-3,(6)+2 1/4|-|-5,3+2,(3)|

$0.(6)= \frac{2}{3} \\ 0.(3)= \frac{1}{3}$


$|-3,(6)+2 \frac{1}{4} |-|-5,3+2,(3)| = \\ = |-3 \frac{2}{3} +2 \frac{1}{4} |-|-5 \frac{3}{10} +2 \frac{1}{3} | = \\ = | - 1 + \frac{1}{4} - \frac{2}{3} | - | - 3 + \frac{1}{3} - \frac{3}{10} | = \\ = | - 1 + \frac{3 - 8}{12} | - | - 3 + \frac{10 - 9}{30} | = \\ = | - 1 \frac{5}{12} | - | - 2 \frac{29}{30} | = \\ = 1 \frac{5}{12} - 2 \frac{29}{30} = \\ = - 1 + \frac{5}{12} - \frac{29}{30} = \\ = - 1 + \frac{25 - 58}{60} = \\ = - 1\frac{23}{60}$