Предмет: Алгебра, автор: pwp2014

Найти область значений функции y=х^2-4x-7, где Є [-2;4]

Ответы

Автор ответа: eVa12741

1

производная
2х-4=0
х=2
(-2)^2+8-7=5
2^2-8-7=-11
4^2-16-7=-7
(-11;5)

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