Question

4х-2(8х-5у)+3(2у-х-3) при х=-1/9 у=1/8

Answer 1

$4x - 16x + 10y + 6y - 3x - 9 =$
$=16 \times \frac{1}{8} - 15 \times ( - \frac{1}{9} ) - 9 = - \frac{16}{3} = - 5 \frac{1}{3}$