Question

Ученикам 8 класса ВОПРОС

Answer 1

b/(b-5)-(4b-1)/(4b-20)=b/(b-5)-(4b-1)/(4(b-5))=(4b-4b+1)/(4(b-5))=1/(4(b-5))
Ответ: 1/(4(b-5))

Answer 2

$\frac{b}{b - 5?} - \frac{4b - 1}{4(b - 5)} = \frac{4b - (4b - 1)}{4(b - 5)} = \frac{4b - 4b \times + 1}{4b - 20} = \frac{1}{4b - 20}$