Question

1) 1/6^4 (одна шестая в четвертой степени)
2) -1/2^6
3) -3 1/3^3
Вычислите:
1) 4^3+3^5 2) 0.6^3-0.4^3 3) 0.12*5^4
Докажите тождество:
4(2-3m)-(6-m)-2(3m+4)=-17m-6

Ребят, заранее пасиб, рили много баллов

Answer 1

$( \frac{1}{6} ) ^{4} = \frac{1}{ {6}^{4} } = \frac{1}{1296} \\ ( - \frac{1}{2} ) ^{6} = \frac{1}{ {2}^{6} } = \frac{1}{64} \\ ( - 3 \frac{1}{3} ) ^{3} = - ( \frac{10}{3} )^{3} = \\ = - \frac{ {10}^{3} }{ {3}^{3} } = - \frac{1000}{27} = - 37 \frac{1}{27}$

${4}^{3} + {3}^{5} = 64 + 243 = 307 \\ (0.6) ^{3} - (0.4) ^{3} = \\ = (\frac{3}{5} ) ^{3} - ( \frac{2}{5} )^{3} = \frac{27 - 8}{125} = \\ = \frac{19}{125}$
$0.12 \times {5}^{4} = 0.12 \times {5}^{2} \times {5}^{2} = \\ = 3 \times 25 = 75$

4•(2-3m)-(6-m)-2•(3m+4)=
=8-12m-6+m-6m-8=
= -17m-6