Question

Решите уравнение :
1-(x-3)^2 = 0

(x+2)^2-0=0

Answer 1

1-(x-3)² = 0 → -(x-3)² = -1 | *(-1) → (x-3)² = 1

x = 2;4.

(x+2)² - 9 = 0 →  (x+2)² = 9 → (x+2) = ±√9 →  x+2 = 3 или x+2 = -3

x = 1;-5.