Question

помогите решить 4 и 5

Answer 1

$4){8}^{5x + 1} = {7}^{5x + 1} \\ ( \frac{8}{7} ) {}^{5x + 1} = 1 \\ ( \frac{8}{7} ) {}^{5x + 1} = ( \frac{8}{7} ) {}^{0} \\ \\ 5x + 1 = 0 \\ 5x = - 1 \\ \\ x = - \frac{1}{5} = - 0.2 \\ \\ 5) \\ 81 {}^{x - 3} = 3 {}^{x} \\ 3 {}^{4x - 4} = {3}^{x} \\ 4x - 4 = x \\ 4x - x = 4 \\ 3x = 4 \\ x = \frac{4}{3} = 1 \frac{1}{3}$

Answer 2

Ответ смотри в приложении.