Question

7x-12>3x+6
5(x+3)>7(x+1)+4
5+|x|>9

Answer 1

$1)\; \; 7x-12>3x+6\\\\4x>18\; ,\; \; x>\frac{18}{4}\; ,\; \; \boxed {x>4,5}\\\\2)\; \; 5(x+3)>7(x+1)+4\\\\5x+15>7x+11\\\\4>2x\; ,\; \; 2x<4\; ,\; \; \boxed {x<2}\\\\3)\; \; 5+|x|>9\\\\|x|>4\; \; \Rightarrow \; \; \left [ {{x>4} \atop {x<-4}} \right. \; \; \Rightarrow \; \; \boxed {x\in (-\infty ,-4)\cup (4,+\infty )}$