Question

1 .  $frac{a}{a-3} - frac{ a^{2} -2a+6}{ a^{2}-3a }$
2.   $frac{ a^{2}+3b}{a} -a$
          При а=0,36        b=2 
3. надо начертить функцию
$y= frac{x^{2}-6x+9 }{3-x}$

Answer 1

$frac{a}{a-3} - frac{ a^{2}-2a+6 }{ a^{2}-3a } = frac{a}{a-3} - frac{ a^{2}-2a+6 }{ a(a-3) }= frac{ a^{2}- a^{2} +2a-6}{a(a-3)} = frac{2(a-3)}{a(a-3)} = frac{2}{a}$

$frac{ a^{2} +3b}{a} -a= frac{ a^{2} +3b- a^{2} }{a} = frac{3b}{a} = frac{3*2}{0.36} = frac{6*100}{36} = frac{100}{6} =16 frac{4}{6} =16 frac{2}{3} =16,666$

$y= frac{ x^{2} -6x+9}{3-x} = -frac{ (x-3)^{2} }{x-3} =3-x$