Question

помогите пожалуйста срочно

Answer 1

$\frac{( {3}^{n} + {3}^{n - 1} ) ^{2} }{ {9}^{n - 1} } = \frac{ {( {3}^{n - 1} \times ( {3}^{n - n + 1} + 1)) }^{2} }{( {3}^{2} )^{n - 1} } = \frac{({3}^{n - 1} \times 4) ^{2} }{ {3}^{2n - 2} } = \frac{{3}^{2n - 2} \times 16}{{3}^{2n - 2}} = 16$

Answer 2

1. (3ⁿ+3ⁿ⁻¹)²=(3ⁿ+3ⁿ/3)²=(3ⁿ+(3ⁿ/3))²=((3*3ⁿ+3ⁿ)/3)²=(4*3ⁿ/3)²=(4*3ⁿ⁻¹)²=16*3²ⁿ⁻².

2. 9ⁿ⁻¹=3²*⁽ⁿ⁻¹⁾=3²ⁿ⁻².

3. 16*3²ⁿ⁻²/3²ⁿ⁻²=16.