Question

Расчитать массовые доли элементов в молекуле CH3COOH

Answer 1

Mr(CH3COOH) = Mr = 2Ar(C) + 4Ar(H) + 2Ar(O) = 2 * 12 + 4 * 1 + 2 * 16 = 60

w(C) = 2Ar(C) / Mr = 24 / 60 = 0.4 = 40%

w(H) = 4Ar(H) / Mr = 4 / 60 = 0.0667 = 6.67%

w(O) = 2Ar(O) / Mr = 32 / 60 = 0.5333 = 53.33%