Question

Помогите плеаааааасссс

Answer 1

$\frac{15(2m-3)}{(3-m)^{3} } +\frac{5m^{2} }{(m-3)^{3} } =-\frac{30m-45}{(m-3)^{3} }+\frac{5m^{2} }{(m-3)^{3} }=\frac{-30m+45+5m^}2} }{(m-3)^{3} }=\frac{5(m^{2}-6m+9) }{(m-3)^{3} }=\frac{5(m-3)^{2} }{(m-3)^{3} }=\frac{5}{m-3}$

$\frac{p^{2}-9q }{(p-3)(q-4)} -\frac{3(p-3q)}{(3-p)(4-q)}=\frac{p^{2}-9q }{(p-3)(q-4)}-\frac{3p-9q}{(p-3)(q-4)}=\frac{p^{2}-9q-3p+9q }{(p-3)(q-4)}=\frac{p^{2}-3p }{(p-3)(q-4)}=\frac{p(p-3)}{(p-3)(q-4)}=\frac{p}{q-4}$