Question

Пожалуста помогите очень надо

Answer 1

$\sqrt[4]{y} =b > 0\\\sqrt[3]{x} =a>0\\\\\left \{ {{a-b=3} \atop {ab=10}} \right. \\\left \{ {{a=b+3} \atop {b^2+3b-10=0}} \right. \\\left \{ {{a=b+3} \atop {b=2}} \right. \\\left \{ {{a=5} \atop {b=2}} \right. \\\left \{ {{\sqrt[3]{x} =5} \atop {\sqrt[4]{y} =2}} \right. \\\left \{ {{x=125} \atop {y=16}} \right.$

Ответ: (125; 16)