Question

Решите плиз алгебру

Answer 1

㏒6(㏒7($\sqrt[12]{7^2}$)) + 9㏒8($\sqrt[3]{2^4}$)=

㏒6(㏒7($\sqrt[6]{7}$)) + 9㏒2^3($\sqrt[3]{2^4}$)=

㏒6(1/6*㏒7(7)) + 9(4/3*3)㏒2(2)=㏒6(1/6*1) + 4*1=-1 + 4= 3

2) $18^{\frac{1}{1+log9(2)}}=18^{\frac{1}{log9(9)+log9(2)}}=18^{\frac{1}{log9(9*2)}}=18^{\frac{1}{log9(18)}}=18^{log18(9)}=9$

3) log√3(5)*log25(6)*log6(27)=

log$3^{1/2}$(5)*log$5^2$(6)*log6($3^3$)=

2*2*3log3(5)*log5(6)*log6(3)=12log3(5)*log5(6)*log6(3)=

12log3(5)*log5(6)*(log5(3)/log5(6))=12log3(5)*log5(3)=

12log3(5)*(1/log3(5))=12