Question

Ученикам 8 класса ВОПРОС

Answer 1

$\frac{6 {x}^{3 } + 48x - 3 {x}^{2} (x + 4)}{ {x}^{3} + 64 } = \frac{6 {x}^{3} + 48x - 3 {x}^{3} - 12 {x}^{2} }{( x + 4)( {x}^{2} - 4x + + 16 }$
$\frac{3 {x}^{3} - 12 {x}^{2} + 48x }{(x + 4)( {x}^{2} - 4x + 16) } = \frac{3x( {x}^{2} - 4x + 16) }{(x + 4)( {x}^{2} - 4x + 16) } = \\ = \frac{3x}{x + 4}$