Question

Задача срочно надо решить

Answer 1

дано

m(ppaKOH) = 56 g

W(KOH) = 10%

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V(SO2)-?

m(KOH) = 56*10% /100%  = 5.6 g

2KOH+SO2-->K2SO3+H2O

M(KOH) = 56 g/mol

n(KOH) = m/M = 5.6 / 56 = 0.1 mol

2n(KOH) = n(SO2)

n(SO2) = 0.1 /2 = 0.05 mol

V(SO2) = n(SO2) * Vm = 0.05 *22.4 = 1.12 L

ответ 1.12 л