Question

Представьте в виде многочлена:
(3z^2-5)(5+3z^2)
(y+3)^2
(a-5)^2
(2b^2-1)^2
(5+3c^2)^2
(c+2)(c^2-c+4)
(y-3)(y^2+3y+9)

Answer 1

(3z²-5)(3z²+5)=9z^4-25;
(y+3)²=y²+6y+9;
(a-5)²=a²-10a+25;
(2b²-1)²=4b^4-4b²+1;
(5+3c²)²=9c^4+30c^2+25;
(c+2)(c²-c+4)=c^3+8;
(y-3)(y²+3y+9)=y^3-27.