Предмет: Физика, автор: kartoshka1276

Самолёт во время разгона, двигаясь равноускоренно из положения покоя, прошел расстояние 500м и оторвался от земли, имея скорость 180км/ч. Определить ускорение самолёта

Ответы

Автор ответа: Samira25032005

Дано:
υ=180 км/ч=50 м/с
S=500 м
------------------
а=?

Решение:
$t = \frac{s}{v} = \frac{500}{50} = 10 \: c$
$a = \frac{v - v0}{t } = \frac{50}{10} = 5$
Ответ: ускорение самолета 5 м/с^2

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