Предмет: Алгебра,
автор: ShkolyarVanya
Найти ОДЗ функции =√ln(x^2−7x+11)/6−x
ShkolyarVanya:
(((
but 2-7+11=5 why did you write like this? i really don't understand
why didn't you write -/ln5
OMG.I incorrectly copied the assignment.I'm an idiot sorry
no don't use like that words please we're human and we can do some mistakes:)
That was weird and confusing.I have corrected.Will you help me?
what's the question
√ln(x^2−7x+11)/6−x :D
ok and what will I gonna do
integral?
Ответы
Автор ответа:
1
I hope this helps you
Приложения:
I'm sorry but why x^2-7x+11=1?
two cases in question in sqrt big and equal 0 and equal 1 that's rule
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