Question

Найдите предел функции Lim х->-3 х^2+5x+6/x^2+6x+9

Answer 1

$\lim \limits _{x - > - 3} \frac{ {x}^{2} + 5x + 6}{ {x}^{2} + 6x + 9 } = \{ \frac{0}{0} \} = \lim \limits _{x - > - 3} \frac{(x + 3)(x + 2)}{(x + 3 {)}^{2} } = \lim \limits _{x - > - 3} \frac{x + 2}{x + 3 } = \frac{ - 1}{0} = \infty$