Предмет: Алгебра,
автор: easyanswer
70 баллов!
1) sinx=a^2-1
2)0.5-sin(11p/12)
Mirage86:
what's the question?
sin(x)=a^2-1
2-1 это вся степень?
Нет, а во второй степени
no 1-sqrt2-sqrt3/2
Ответы
Автор ответа:
2
I hope this helps you
Приложения:
but i don't understand what you want
ask again but completely
tg(9p/8)-1=
=tg((p/8)+p)-1=-tg(p/8)-1<0
answer: minus
It's answers other variant, but tasks are similar, it can help you
=tg((p/8)+p)-1=-tg(p/8)-1<0
answer: minus
It's answers other variant, but tasks are similar, it can help you
check now please
I need a solution of another example (0.5-sin(11p/12))
the answer should be something like I wrote above in the comments (where I wrote a similar example and its solution)
the answer should be something like I wrote above in the comments (where I wrote a similar example and its solution)
ok i add it again
i hope, it's will be true
I'm sure my answers:)
are correct :)
thanks)
Автор ответа:
0
task/29655181
1. sinx = a² - 1 Уравнение имеет решение , если
- 1 ≤ a² - 1 ≤ 1 ⇔ 0 ≤ a² ≤ 2 ⇔ - √2 ≤ a ≤ √2 * * * a ∈ [ - √2; √2 ]
x =( -1)⁻ⁿ arcsin(a² - 1 ) + πn , n ∈ ℤ .
* * * a ∈ ( - ∞ ; - √2) ∪ (√2 ; ∞) → нет решения x ∈ ∅ * * *
2. 0,5 - sin(11π/12) =0,5 - sin(π -π/12) = 0,5 - sin(π/12) = 0,5*( 1 - √(2 -√3) ) , т.к.
sin(π/12) = √[ ( 1 -cos(π/6) ) /2] = 0,5√(2 -√3)
* * * √(2 -√3) =√( 2(4 - 2√3) / 4) = √( 2(√3 - 1)² /4 ) = 0,5 (√3 - 1)√2 * *
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