Question

Сократите дробь
пожалуйста!!!

Answer 1

1. 2ⁿ⁺¹*x-2ⁿ⁺²=2*2ⁿ*x-2²*2ⁿ=2ⁿ*(2x-4)=2*2ⁿ*(x-2).

2. 2ⁿ*x²-2ⁿ⁺²=2ⁿ*x²-2²*2ⁿ=2ⁿ*(x²-4)=2ⁿ*(x-2)*(x+2)

3. 2*2ⁿ*(x-2)/(2ⁿ*(x-2)*(x+2))=2/(x+2).

Answer 2

$\displaystyle\tt \frac{2^{n+1}\cdot x-2^{n+2}}{2^n\cdot x^2-2^{n+2}}=\frac{2^{n}\cdot 2\cdot x-2^{n}\cdot2^2}{2^n\cdot x^2-2^{n}\cdot2^2}=\frac{2^{n}(2x-2^2)}{2^n(x^2-2^2)}=\frac{2x-4}{(x-2)(x+2)}=\\\\\\= \frac{2(x-2)}{(x-2)(x+2)}=\frac{2}{x+2}$