Question

решите систему уравнений {x+y=10/{x^2-y^2=40

Answer 1

$\left \{ {{x+y=10} \atop {x^2-y^2=40}} \right.;\,\,\,\,\,\,\,\,\,\left \{ {{x+y=10} \atop {(x-y)(x+y)=40}} \right.\,\,\,\,\,\,\,\left \{ {{x+y=10} \atop {10(x-y)=40}} \right.;\,\,\,\,\,\,\,\,\left \{ {{x+y=10} \atop {x-y=4}} \right.$

Сложим уравнения 2x = 14

x = 7

y = 10 - x = 10 - 7 = 3

otvet: (7;3)