Question

Решить уравнение:
2x^2-x(222-40x)=70+20(3x-x^2)

Answer 1

$2x^2-x(222-40x)=70+20(3x-x^2)\2x^2-222x+40x^2=70+60x-20x^2\62x^2-282x-70=0\31x^2-141x-35=0\D=19881+4340=24221\x_1=frac{141-sqrt{24221}}{62};,;;x_2=frac{141+sqrt{24221}}{62}$