Question

(№133) Решите пожалуйста! ОБЯЗАТЕЛЬНО С РЕШЕНИЕМ СНИЗУ !

Answer 1

$\displaystyle \tt 133.\\\\1). \ \ \frac{3}{7}:k=5:2\frac{1}{3}\\\\. \ \ \ \ \ \frac{3}{7}:k=5:\frac{7}{3}\\\\. \ \ \ \ \ 5k=\frac{3}{7}\cdot \frac{7}{3}\\\\. \ \ \ \ \ 5k=1\\\\. \ \ \ \ \ k=\frac{1}{5}\\\\. \ \ \ \ \ k=0,2\\\\\\2). \ \ k:\frac{5}{9}=1,8:6\\\\. \ \ \ \ \ 6k=\frac{5}{9}\cdot \frac{18}{10}\\\\. \ \ \ \ \ 6k=1\\\\. \ \ \ \ \ k=\frac{1}{6}\\\\\\3). \ \ 5,5:8=k:\frac{2}{11}\\\\. \ \ \ \ \ 8k=\frac{55}{10}\cdot \frac{2}{11}\\\\. \ \ \ \ \ 8k=1\\\\. \ \ \ \ \ k=\frac{1}{8}\\\\. \ \ \ \ \ k=0,125$

$\displaystyle \tt 4). \ \ 20:3,25=\frac{4}{13}:k\\\\. \ \ \ \ \ 20:\frac{13}{4}=\frac{4}{13}:k\\\\. \ \ \ \ \ 20k=\frac{13}{4}\cdot \frac{4}{13}\\\\. \ \ \ \ \ 20k=1\\\\. \ \ \ \ \ k=\frac{1}{20}\\\\. \ \ \ \ \ k=0,05$