Question

Пж решите (6x-13)(7x-42)(0,26-0,12x)=0
Срочно надо

Answer 1

$(6x - 13)(7x - 42)(0.26 - 0.12x) = 0\\ 1. \\ 6x - 13 = 0 \\ 6x = 13 \\ x = 2 \frac{1}{6} \\ 2. \\ 7x - 42 = 0 \\ 7x = 42 \\ x = 6 \\ 3. \\ 0.26 - 0.12x = 0 \\ 0.12x = 0.26 \\ x = \frac{0.26}{0.12} = \frac{26}{12} = \frac{13}{6} = 2 \frac{1}{6}$
Ответ: все три икса