Question

решите, пожалуйста, 5 и 7 номер

Answer 1

$\frac{(3^{7} *(3^{2})^{3})}{3^{10} }=\frac{3^{7}*3^{6}}{3^{10} }=3^{7+6-10}=3^{3}=27\\\\\frac{(5^{3}*2^{3})}{10^{2} }=\frac{(5*2)^{3} }{10^{2} }=\frac{10^{3} }{10^{2} }=10\\\\\frac{2^{8}*(7^{2})^{4}}{14^{7} }=\frac{2^{8} *7^{8} }{14^{7} }=\frac{(2*7)^{8} }{14^{7} }=\frac{14^{8} }{14^{7} } =14\\\\\frac{5^{6}*125 }{25^{4} } =\frac{5^{6} *5^{3} }{(5^{2} )^{4} } =\frac{5^{9} }{5^{8} }=5$

Answer 2

$1) \\ \frac{ {3}^{7} \times {3}^{6} }{ {3}^{10} } = \frac{ {3}^{13} }{ {3}^{10} } = { 3}^{3} = 27 \\ \\ 2) \\ \frac{ {10}^{3} }{ {10}^{2} } = 10 \\ \\ 3) \\ \frac{ {2}^{8} \times {7}^{8} }{ {14}^{7} } = \frac{ {14}^{8} }{ {14}^{7} } = 14 \\ \\ 4) \frac{ {5}^{6} \times {5}^{3} }{ {5}^{8} } = \frac{ {5}^{3} }{ {5}^{2} } = 5$