Question

С 7 по 12 пожалуйста срочно надо 20 баллов

Answer 1

$\boxed {\frac{1}{a}=a^{-1}\; \; \; ,\; \; \; \frac{1}{a^{-1}}}\\\\\\-4^{-3}=-(4^{-3})=-\frac{1}{4^3}=-\frac{1}{64}\\\\(-0,3)^{-2}=\frac{1}{(-0,3)^2}=\frac{1}{+0,3^2}=\frac{1}{0,09}=\frac{1}{9/100}=\frac{100}{9}=11\frac{1}{9}\\\\(-2\frac{1}{2})^{-2}=(-\frac{5}{2})^{-2}=\frac{1}{(-5/2)^2}=\frac{1}{25/4}=\frac{4}{25}=0,16\\\\(-2,25)^{-1}=\frac{1}{-2,25}=-\frac{1}{9/4}=-\frac{4}{9}\\\\-(-2,3)^{-1}=-\frac{1}{-2,3}=\frac{1}{2,3}=\frac{1}{23/10}=\frac{10}{23}\\\\-(-2\frac{1}{3})^{-2}=-(-\frac{7}{3})^{-2}=-\frac{1}{(-7/3)^2}=-\frac{1}{49/9}=-\frac{9}{49}$