Question

СРОЧНО, МНОГО БАЛЛОВ
1) w(C)=85,71% , M(CₓHₐ)=28 г/моль , CₓHₐ-?
2) w(C)=92,3% , D(H₂)=13 , CₓHₐ-?
(вивести формули речовин)

Answer 1

1)
$28 = 100\% \\ c = 85.71\%$
M(C) = $\frac{28 \times 85.71}{100} = 23.9988 = 24$
M(H) = $28 - 24 = 4$
n(C) = $\frac{24}{12} = 2$
n(H) = $\frac{4}{1} = 4$
Ответ: C2H4

2)
M(CxHa) = D(H2) × M(H2) = $13 \times 2 = 26$
$26 = 100\% \\ c = 92.3\%$
M(C) = $\frac{92.3 \times 26}{100} = 23.998 = 24$
M(H) = $26 - 24 = 2$
n(C) = $\frac{24}{12} = 2$
n(H) = $\frac{2}{1} = 2$
Ответ: C2H2

Вроде бы так