Question

Вычислите номер 36, опишите подробно.

Answer 1

$1)\sqrt[5]{32}-0,5\sqrt[3]{-216} =\sqrt[5]{2^{5}}-0,5\sqrt[3]{(-6)^{3}} =2-0,5*(-6)=2+3=5 \\\\2)\sqrt[3]{-1000}-\frac{1}{4}\sqrt[4]{256}=\sqrt[3]{(-10)^{3}} -\frac{1}{4} \sqrt[4]{4^{4}} =-10-\frac{1}{4}*4=-10-1=-11\\\\\sqrt[5]{\frac{1}{243}} +\sqrt[3]{-0,001}-\sqrt[4]{0,0016}=\sqrt[5]{(\frac{1}{3})^{5}}+\sqrt[3]{(-0,1)^{3}}-\sqrt[4]{(0,2)^{4}} =\frac{1}{3} -0,1-0,2=\frac{1}{3} -0,3=\frac{1}{30}$

Answer 2

$1) \sqrt[5]{32} - 0.5 \sqrt[3]{ - 216} = 2 - 0.5 ( - 6) = 2 + 3 = 5 \\ \\ 2) \sqrt[3]{ - 1000} - \frac{1}{4} \times \sqrt[4]{256} = - 10 - \frac{1}{4} \times 4 = - 10 - 1 = - 11 \\ \\ 3) \sqrt[5]{ \frac{1}{243} } + \sqrt[3]{ - 0.001} - \sqrt[4]{0.0016} = \frac{1}{3} + \sqrt[3]{ - \frac{1}{1000} } - \sqrt[4]{ \frac{1}{625} } = \frac{1}{3} - \frac{1}{10} - \frac{1}{5} = \frac{1}{30}$