Question

Помогите, пожалуйста! По алгебре!

Answer 1

$1)\; \; 3-\frac{x}{5}=x\\\\3=x+\frac{x}{5}\\\\3=\frac{6x}{5}\\\\x=\frac{3\cdot 5}{6}\\\\x=\frac{5}{2}\\\\x=2,5\\\\2)\; \; (\frac{5}{6}+1\frac{1}{10})\cdot 24=(\frac{5}{6}+\frac{11}{10})\cdot 24=\frac{5\cdot 5+11\cdot 3}{30}\cdot 24=\frac{25+33}{30}\cdot 24=\\\\=\frac{58\cdot 24}{30}=\frac{29\cdot 2\, \cdot \, 3\cdot 8}{5\cdot 2\cdot 3}=\frac{29\cdot 8}{5}=\frac{232}{5}=46,4$