Question

Первый курс, юрисдикция

Answer 1

$z_{1}=3-2i; z_{2}=2+2i\\ z_{1}+z_{2}=(3+2)+(-2+2)i=5\\ z_{1}-z_{2}=(3-2)+(-2-2)i=1-4i\\ z_{2}-z_{1}=(2-3)+(2--2)i=-1+4i\\ z_{1}*z_{2}=6+6i-4i+4=10+2i\\ \frac{z_{1}}{z_{2}}=\frac{3-2i}{2+2i} =\frac{(3-2i)(2-2i)}{(2+2i)(2-2i)}=\frac{6-6i-4i+4}{4+4} =\frac{10-10i}{8} =1.25-1.25i\\ \frac{z_{2}}{z_{1}}=\frac{2+2i}{3-2i}=\frac{(2+2i)((3+2i)}{(3-2i)(3+2i)} =\frac{6+4i+6i-4}{9+4} =\frac{2+10i}{13} =\frac{2}{13} +\frac{10}{13} i$