Предмет: Физика, автор: fuljfkbyf

Дам 34 баллов на сколько градусов нагреется 2 кг воды при сжигании 200 грамм керосина? q=46Мдж/кг c=4200Дж/кг*C

Ответы

Автор ответа: mrtolik42

0

m=2 кг {воды) Qтоп =mт*q Qтоп= Qвод тогда

m=0.2 кг (топлива ) Qвод=cmt t = (mт*q )/ cmвод

q = 46*1000000 Dж/кг (топлива) t = 109

с= 4200 Дж/кг*С (удел воды)

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