Question

Решите уравнение
2x²-7x-4/2x²+x
За ранее спасибо

Answer 1

$\frac{2x^{2}-7x-4 }{2x^{2}+x } \\\\2x^{2}-7x-4=0\\\\D=(-7)^{2}-4*2*(-4)=49+32=81=9^{2}\\\\x_{1}=\frac{7+9}{4} =4\\\\x_{2}=\frac{7-9}{4}=-\frac{1}{2}\\\\2x^{2}-7x-4=2(x-4)(x+\frac{1}{2})=(x-4)(2x+1)\\\\\frac{2x^{2}-7x-4 }{2x^{2}+x }=\frac{(x-4)(2x+1)}{x(2x+1)}=\frac{x-4}{x}$